7=1/2(2x^2-3x)

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Solution for 7=1/2(2x^2-3x) equation: 



7=1/2(2x^2-3x)

We move all terms to the left:

7-(1/2(2x^2-3x))=0



Domain of the equation: 2(2x^2-3x))!=0

x∈R



We multiply all the terms by the denominator


-(1+7*2(2x^2-3x))=0



We calculate terms in parentheses: -(1+7*2(2x^2-3x)), so:

1+7*2(2x^2-3x)

determiningTheFunctionDomain
7*2(2x^2-3x)+1

Wy multiply elements

14x(2+1

Back to the equation:

-(14x(2+1)



We add all the numbers together, and all the variables

-(14x3=0

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